Question

find the zeroes pf the polynomial x²-9​

Answer 1

p(x) = x²-9

p(x) = x² - 3²

p(x) = (x-3)(x+3)

(x-3)(x+3) = 0

x-3 = 0

x = 3

and

x+3 = 0

x = -3

Therefore,the zeroes of the given polynomial are 3 and -3.

Hope it helps.