Question

find the zeroes x²+1/x×x-2

Answer 1

Answer- Let p(x)= x²+1/x×x-2        
                          = x²+1-2                   
                          = x²-1
To find zero of polynomial,
p(x)= 0
x²-1=0
x²=1
x=√1
x= 1
So, x=1 is the zero of the given polynomial.

Please mark as the BRAINLIEST answer if helpful.

Answer 2

Answer:

$\huge{\boxed{\boxed{\bf{x=1}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\bf{SOLUTION-}}}}}$

=) x² + 1/ x × x - 2

=) x² + 1 - 2

=) x² - 1

$for \: finding \: zeroes \\ = ) p(x) = 0 \\ = ) {x}^{2} - 1 = 0 \\ = ) {x}^{2} = 1 \\ = )x = \sqrt{1} \\ = )x = 1$

$\huge{\boxed{\boxed{\bf{x=1}}}}$

$\huge{\boxed{\boxed{\underline{\bf{VERIFICATION}}}}}$

>> PUTTING VALUE OF X IN GIVEN QUESTION.

$= ) {x}^{2} + \frac{1}{x \times( x - 2)} \\ = ) {1}^{2} + \frac{1}{1 \times (1 - 2)} \\ = )1 + \frac{1}{ - 1} \\ = ) 1 - 1 \\ = )0 \\ it \: comes \: zero \: bcz \: the \: value \: of \: \\ x \: is \: zerores \: of \: this \: eqn$

$\huge{\boxed{\boxed{\underline{\bf{VERIFIED}}}}}$