Question

find the zeroes x²-10x+24​

Answer 1

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find the zeroes x²-10x+24

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$➩ {x}^{2} - 10x + 24 = 0$

$➩ {x}^{2} - 12x + 2x + 24 = 0$

$➩x(x - 12) - 2(x - 12)$

$➩(x - 2)(x - 12)$

$➩x = 2 \: and \: x = 12$

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