Question

find the zeroes x2 - 2x - 8 ​

Answer 1

⭐Ⓢⓞⓛⓤⓣⓘⓞⓝ ⭐

${x}^{2} - 2x - 8 = 0 \\ \\ {x}^{2} - 4x + 2x - 8 = 0 \\ \\ x(x - 4) + 2(x - 4 )= 0 \\ \\ (x - 4)(x + 2) = 0$

➡ Zeroes are 4 and -2 respectively.

ℏ✺℘ḙ !т ℏḙℓ℘ṧ ❤