Question

Find the zeroes
x²+3x+2​

Answer 1

Answer:

x^+3x+2

=x^+x+2x+2

=x(x+1) +2(x+1)

=(x+1) (x+2)

either,

(x+1) =0 or (x+2) =0

=x=-1 =x=-2

hence the zeroes are -1 &-2

Answer 2

Answer:

-1 or -2

Step-by-step explanation:

first factorise it...

x² + x + 2x + 2 (by middle term splitting)

x(x + 1) + 2(x + 1)

(x + 1)(x + 2)

take any of them

eg: I am taking (x + 1)

so, x + 1 = 0

x = -1

therefore the zero of polynomial will be -1 or -2