find the zeroesof polynomialp(x)=6x×x-3-7x
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Answered by
1
6x^2 -7x-3
6x^2-9x+2x-3
3x(2x-3) 1(2x-3)
(3x+1)(2x-3)
therefore zeroes are x=-1/3 and 3/2
hope it helps you out
Happy Diwali
6x^2-9x+2x-3
3x(2x-3) 1(2x-3)
(3x+1)(2x-3)
therefore zeroes are x=-1/3 and 3/2
hope it helps you out
Happy Diwali
Answered by
1
p(x)=6x.x-3-7x
let x=0=>p(0)=6×0×0-3-7×0
=0-10×0=>0-0=>0
let x=1=>p(1)=6×1×1-3-7×1
=6-10=>-4
let x=-1=>p(-1)=6×(-1)×(-1)-3-7×(-1)
=(-6)×(-1)-10×(-1)=>(-6)-(-10)=>4
let x=2=>p(2)=6×2×2-3-7×2
=24-10×2=>24-20=>4
let x=-2=>p(-2)=6×(-2)×(-2)-3-7×(-2)
=(-12)×(-2)-(10)×(-2)=>(-24)-(20)=>4
hope this helps U
mark brainlist
let x=0=>p(0)=6×0×0-3-7×0
=0-10×0=>0-0=>0
let x=1=>p(1)=6×1×1-3-7×1
=6-10=>-4
let x=-1=>p(-1)=6×(-1)×(-1)-3-7×(-1)
=(-6)×(-1)-10×(-1)=>(-6)-(-10)=>4
let x=2=>p(2)=6×2×2-3-7×2
=24-10×2=>24-20=>4
let x=-2=>p(-2)=6×(-2)×(-2)-3-7×(-2)
=(-12)×(-2)-(10)×(-2)=>(-24)-(20)=>4
hope this helps U
mark brainlist
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