Question

find the zerores of the following quadratic polynomial. a. x^2-x-6.
b. x^2-5x+4​

Answer 1

Answer:

x²- x -6

x²-3x +2 x - 6 = 0

x(x- 3) + 2(x - 3) = 0

x+2=0 x -3= 0

x= -2 x= 3

x²-5x+4=0

x²+4x +x +4= 0

x(x+4) + 1(x+ 4) = 0

x+1= 0. x+4=0

x=-1. x= -4

I hope it will help you mate!