Question

find the zeros
7y²-11/3y-2/3

Answer 1

zeroes are -1/7 , 2/3
.......hope it helps.....

Answer 2

Hello dear !
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 Given polynomial = 7y² - 11/3y - 2/3 
                             = 21y² - 11y  - 2 (Multiply full polynomial by 3 )
                             = 21y² -14y+3y - 2 
                             = 7y(3y-2) +1(3y-2)
                             = (3y-2) (7y+1)
                             = y = 2/3 OR -1/ 7 
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