Question

find the zeros and check the relationship root 2 x square - 3 x minus 2 root 3​

Answer 1

Answer:

P(X) => 4✓3X²+5X-2✓3

=> 4✓3X² + 8X -3X - 2✓3

=> 4X ( ✓3X + 2) - ✓3( ✓3X + 2)

=> (✓3X +2) ( 4X- ✓3) = 0

=> (✓3X+2) = 0 OR (4X-✓4) = 0

=> X = -2/✓3 OR X = ✓4/4

Let Alpha = -2/✓3 and Beta = ✓4/4

Relationship between zeroes and Coefficient

Sum of zeroes = Alpha + Beta = ( -2/✓3 + ✓4/4) = -8 + 4/4✓3 = -5/ 4✓3 = - (Coefficient of X/Coefficient of X²) 

And,

Product of zeroes = Alpha × Beta = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

P(X) => 4✓3X²+5X-2✓3

=> 4✓3X² + 8X -3X - 2✓3

=> 4X ( ✓3X + 2) - ✓3( ✓3X + 2

=> (✓3X +2) ( 4X- ✓3) = 0

=> (✓3X+2) = 0 OR (4X-✓4) = 0

=> X = -2/✓3 OR X = ✓4/4

Let Alpha = -2/✓3 and Beta = ✓4/4

Relationship between zeroes and Coefficient