Question

Find the zeros and number of zeros of p(x)=x²+9x+18. Show them on a graph.

Answer 1

Final Answer : -3,-6

Steps:
1)
$p(x) = 0 \\ => p(x) = x^2 + 9x + 18 \\=> x^2+6x+3x+18 = 0\\ => x (x+6) + 3(x+6) =0 \\ => (x+6) (x+3)= 0 \\ =>x = -3 \: or \: x = -6$

Here, p(x) is quadratic Polynomial with leading co-efficient positive.
Hence, Graph of p(x) is upward Parabola.
It intersects x -axis at x = -3, -6 .