Question

find the zeros and relationship between the zeros and the coefficient
$2x ^{2} - 7x + 3 = 0$
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Answer 1

Answer:

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Step-by-step explanation:

$2x {}^{2} - 7x + 3 = 0$

By using the Shree Dhracharya Formula

$x = \frac{ - b( + -) \sqrt{b {}^{2} - 4ac } }{2a}$

$x = \frac{ (7( + - ) \sqrt{49 - 24} ) }{4} \\ = \frac{7( + - )5 }{4} \\ = \frac{7 + 5}{4} \: \: \: and \: \frac{7 - 5}{4} \\ = 3 \: \: and \: \: \frac{1}{2}$

So the root of the equation is 3 and 1/2 .