Question

Find The zeros and varify the relationship between zeros and coefficient of x2-9

Answer 1

Step-by-step explanation:

here is your answer and once try to solve it yourself

Answer 2

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☆ Given Polynomial:-

• x²-9

☆ To find:-

• The zeroes of the given polynomial.

☆ Now,

• To find the zeroes x²-9 must be = 0

=》 x²-9 = 0

=》 x² = 9

=》 x² = (+3)² or (-3)²

=》 x = 3 or -3

● Verification:-

We know that sum of the zeroes

= -co-efficient of x/coefficient of x²

So,

3+(-3) = 3-3 = 0

Also

= -co-efficient of x/coefficient of x²

= 0.

{since x²-9 can be written as x²-0x-9}

And

Product of zeroes

= constant term/coefficient of x²

So,

3×(-3) = -9 = constant term/coefficient of x²

Therefore,

Sum of the zeroes = -b/a

And,

Product of the zeroes = c/a

Hence verified.

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