Question

find the zeros and verify
the relationship between
the zeros and the
coefficient of 6s²-3-7s​

Answer 1

Step-by-step explanation:

$6s {}^{2} - 7s - 3 \\6s {}^{2} - 2s + 9s - 3 \\ 2s (3s - 1) + 3(3s - 1) \\ 2s + 3 \: or \: 3s - 1 \\ s = - \frac{3}{2} and \: \frac{1}{3} \\ sum \: ofzeroes \: = \frac{ - 7}{6} \\ sum \: of \: coefficient \: = \frac{ - b}{a} = -\frac{ - 7}{6} \\ product \: of \: zeroes = \frac{ - 1}{3} \\ product \: of \: coefficient \: = \frac{c}{a} = \frac{ - 3}{6} = - \frac{1}{3}$

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