Question

Find the zeros and verify the relationship between the zeros and coefficients of the quadratic polynomial 4x^2 +4x – 3 give answere properly or elese I will report you account​

Answer 1

Let f(x) = 4x2 ˗ 4x ˗ 3 = 4x2 ˗ (6x ˗ 2x) ˗ 3 = 4x^2 ˗ 6x + 2x ˗ 3 = 2x (2x ˗ 3) + 1(2x ˗ 3) = (2x + 1) (2x ˗ 3) To find the zeroes, set f(x) = 0 (2x + 1) (2x ˗ 3)= 0 2x + 1 = 0 or 2x ˗ 3 = 0 x = -1/2 or x = 3/2 Again, Sum of zeroes = (-1/2) + (3/2) = (-1+3)/2 = 2/2 = -b/a = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = (-1/2)(3/2) = (-3)/4 = c/a

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Answer 2

Answer:

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Step-by-step explanation:

4x2 +6x-2x-3

2x (x-2) +2(x-2)

(2x+2)(x-2)

zeroes -1and 2

sum of zeroes -1 +2

=1

=-coefficient of x/coefficient of x2

product of zeroes =-2

=constant term /coefficient of x2

hence verified