find the zeros by quadratic equation 6x2-7x-3
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Answer:x= -1/3, x=3/2
Step-by-step explanation:
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6x2-7x-3
Doing middle term split
6x2-9x+2x-3
3x(2x-3)+1(2x-3)
(3x+1)(2x-3)
3x+1=0 or 2x-3=0
Therefore the zeros are -1/3 and 3/2
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