Question

find the zeros for given polynomial √3xsquere + 10x + 7√3​

Answer 1

Answer:

$x = - \sqrt{3} \: \: \: \: \: and \: \: \: \: \: \: \: x = - \frac{7}{ \sqrt{3} }$

Step-by-step explanation:

$\sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} = 0 \\ \\ \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} = 0 \\ \\ \sqrt{3} x(x + \sqrt{3} ) + 7(x + \sqrt{3} ) = 0 \\ \\ (x + \sqrt{3} )( \sqrt{3} x + 7) = 0 \\ \\ x = - \sqrt{3} \\ \\ x = - \frac{7}{ \sqrt{3} }$

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Answer 2

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$\sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} = 0 \\ </p><p></p><p> = > \sqrt{3} {x}^{2} + (7 + 3)x + 7 \sqrt{3} = 0 \\ </p><p></p><p>= > \sqrt{3} {x}^{2} + 7x + 3x + 7 \sqrt{3} = 0 \\ </p><p></p><p>= > x( \sqrt{3} x + 7) + \sqrt{3} ( \sqrt{3} x + 7) = 0 \\ </p><p></p><p>= > (x + \sqrt{3} )( \sqrt{3} x + 7) = 0 \\ so \\ x + \sqrt{3} = 0 \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: \: \: \sqrt{3} x + 7 = 0 \\ = > x = - \sqrt{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > x = - \frac{7}{ \sqrt{3} }$

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