Question

Find the zeros if 3x^2 -3 and verify the relationship between the zeros and the coefficients

Answer 1

Answer:

3x^2 - 3

3 ( x^2 - 1 )

for 3 zero is 0

x ^2-1 = 0

x^2 = 1

x= root 1

x = 1

alpha + bheta = -0/1 = 0 = -b/a

alpha × bheta = 0× 1 = 0 = c / a

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Answer 2

Answer:

given

3x^2-3=0

→3(x^2-1)=0

→3(x+1)(x-1)=0→x=1 it x= -1

Step-by-step explanation