Question

find the zeros if poomial x²-x-2

Answer 1

$\huge\rm\color{midnightblue}{Solution:-}$

$\rm x{}^{2}-x-2$

$\rm x{}^{2}-(2-1)x-2$

$\rm x{}^{2}-2x+x-2$

$\rm x(x-2)+1(x-2)$

$\rm (x-2)(x+1)$

$\sf Zero's$

¡) x-2=0

x=2

¡¡) x+1=0

x=(-1)

The zero's are 2 and (-1)

Answer 2

Let the given polynomial be p(x)

$\sf{p(x) = x {}^{2} - x - 2 }$

By Remainder Therom,

p(x)=0

Implies,

$\sf{x {}^{2} - x - 2 = 0 } \\ \\ \implies \: \sf{x {}^{2} - 2x + x - 2= 0 } \\ \\ \implies \: \sf{(x - 2)(x + 1) = 0}$

If you want to find the zeros;

x - 2 = 0 and, x + 1=0

»x=2 or -1

Henceforth,the zeros of the polynomial are 2 and -1