Question

find the zeros of 2x^2-7x+6 and verify zeros and coefficients​

Answer 1

Answer:

2x^2+7x+6

2x^2+4x+3x+6

split 7x into 4x and 3x

2x(x+2)+3(x+2)

(2x+3)(x+2)

x=-3/2 or x=-2

Answer 2

Answer:

zeroes are 3/2 and 2

Step-by-step explanation:

2x² - 7x + 6 = 0

2x² - (4+3)x + 6 = 0

2x² - 4x - 3x + 6 = 0

2x(x - 2).-3(x - 2)= 0

(2x - 3)(x - 2) = 0

2x - 3 = 0 , x - 2 = 0

2x = 3 , x = 2

x = 3/2 , x = 2

verification

sum of zeroes = -b/a

3/2 + 2 = -(-7/2)

(3+4)/2 = 7/2

7/2 = 7/2

product of zeroes = c/a

3/2 × 2 = 6/2

3 = 3