Question

find the zeros of 2x^4-3x^3-3x^2+6x-2, if you that the two of its zerosare√2 and -√2​

Answer 1

Answer:

Step-by-step explanation:

Two zeroes are given : $\sqrt2$ and $-\sqrt2$

So, two factors are: $(x-\sqrt2)(x+\sqrt2) = (x^2 -2)$

Divide the given equation by this factor$(x^2-2)$ :

You will get a quadratic equation which you can solve easily to find the zeroes.

Answer 2

Answer:

Step-by-step explanation:

Here is your answer

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Hope it will help you......