find the zeros of
2x²+10x+12
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GudduPatel:
solution.....- 2x^2+10x+12 =2x^2+6x+4x+12=2x(x+3)+4(x+3)=(x+3)(2x+4).......
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Answered by
1
2x2+6x+4x+12=0
2x(x+3)+4(x+3)=0
(x+3)(2x+4)=0
x=-3,-2
sum =-3-2=-5
product= -3(-2)=6
x2+(sum of zeroes)x+product of zeroes
x2-5x+6=0. this is required equation
Answered by
1
Given
2x^2+10x+12
Now 2x^2+10+12= 2x^2+6x+4x+12
=2x(x+3)+4(x+3)
=(x+3)(2x+4)
Now for the zeroes of the given polynomial,
(x+3)(2x+4)=0
either x+3=0
=x=-3
or,2x+4=0
=2x=-4
=x=-4/2
=x=-2
Hence the zeroes of the given polynomial =-3 and-2
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