Question

find the zeros of √2x2-3x-2√2​

Answer 1

Step-by-step explanation:

$p(x) = \sqrt 2x {}^{2} - 3 x - 2 \sqrt{2}$

1. $p(x) = 0$
2. $\sqrt2x ^{2} - 3x - 2 \sqrt[]2 = 0$
3. $\sqrt2x ^{2} - 4x + x - 2 \sqrt[]2 = 0$
4. ,
5. $\sqrt 2x(x \ - 2 \sqrt 2) + 1(x - 2 \sqrt2) = 0$
6. $(x - 2 \sqrt 2)( \sqrt2x + 1) = 0$
7. $x - 2 \sqrt2 = 0 \: \: \: or \sqrt2x + 1 = 0$