Math, asked by avinashdevasi, 1 year ago

find the zeros of 2x²+7x²-24x-45 and also find its factors

Answers

Answered by lpskshatri
1
2x3+7x2-24x-45
 \alpha  +  \beta  +  \gamma  = \frac{ - b}{a}
-7/2

alpha beta+beta gamma +gammaalpha=c/a
-24/2
-12
alpha ×beta× gamma =-d/a
-(-45)/2.
45/2

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