Find the zeros of √3×x2+10x+7√3
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Answered by
7
√3x² + 10x + 7√3
=√3x² + 3x + 7x + 7√3
=√3x ( x + √3) + 7(x + √3)
=(√3x + 7)(x + √3)
here ( √3x + 7) and (x + √3) are the factors of given polynomial so,
x = -7/√3 and -√3 are the zeros of given polynomial
=√3x² + 3x + 7x + 7√3
=√3x ( x + √3) + 7(x + √3)
=(√3x + 7)(x + √3)
here ( √3x + 7) and (x + √3) are the factors of given polynomial so,
x = -7/√3 and -√3 are the zeros of given polynomial
Answered by
4
Hi Friend,
Here is your answer,
According to the question,
√3x² + 10x + 7√3
√3x² + 3x + 7x + 7√3
√3x ( x + √3) + 7(x + √3)
(√3x + 7)(x + √3)
So, ( √3x + 7) and (x + √3) are the factors!
x = -7/√3 and -√3 are the zeros of polynomial
Hope it helps you!
Here is your answer,
According to the question,
√3x² + 10x + 7√3
√3x² + 3x + 7x + 7√3
√3x ( x + √3) + 7(x + √3)
(√3x + 7)(x + √3)
So, ( √3x + 7) and (x + √3) are the factors!
x = -7/√3 and -√3 are the zeros of polynomial
Hope it helps you!
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