Find the zeros of 3k≠k(k-3)
Answers
Answered by
1
Step-by-step explanation:
Compare given Quadratic polynomial kx²+2x+3k by
ax²+bx+c , we get
a = k , b = 2 , c = 3k
i ) Sum \:of \:the \:zeroes = \frac{-b}{a}\\=\frac{-2}{k}--(1)
ii) Product \:of \: the \: zeroes = \frac{c}{a}\\=\frac{3k}{k}\\=3--(2)
According to the problem given,
sum of the zeroes is equal to their product.
\frac{-2}{k}=3
\implies -2=3k
\implies \frac{-2}{3}=k
Therefore,
value \: of \: k = \frac{-2}{3}
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Answered by
5
Answer:
⭐K≠0 or ⭐k≠6
Step-by-step explanation:
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=>3k≠k(k-3)
=>3k≠k^2-3k
=>k^2≠6k
=>k^2-6k≠0
=>k(k-6)≠0
=>k≠0 or =>k≠6
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