Find the zeros of 3x^2-2x-7
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Here's your answer mate...
![3 {x}^{2} - 2x - 7 \\ \\ x(3 x - 2) - 7 \\ \\ (x - 7)(3x - 2) 3 {x}^{2} - 2x - 7 \\ \\ x(3 x - 2) - 7 \\ \\ (x - 7)(3x - 2)](https://tex.z-dn.net/?f=3+%7Bx%7D%5E%7B2%7D++-+2x+-+7+%5C%5C++%5C%5C++x%283+x+-+2%29+-+7+%5C%5C++%5C%5C+%28x+-+7%29%283x+-+2%29)
Hope it Helps!!
Hope it Helps!!
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