Question

Find the zeros of √3x square+10x+7√3

Answer 1

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Answer 2

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$\sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} = 0\\ \\ \sqrt{3} {x}^{2} + 7x + 3x + 7 \sqrt{3} = 0 \\ \\ x( \sqrt{3} + 7) + \sqrt{3} ( \sqrt{3} x + 7) = 0 \\ (x + \sqrt{3} )( \sqrt{3} x + 7) = 0 \\ \\ x = - \sqrt{3} \: and \: x = \frac{ - 7}{ \sqrt{3} } = \frac{ - 7 \sqrt{3} }{3}$



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