Math, asked by Anonymous, 1 year ago

find the zeros of √3x²+10x+7√3

Answers

Answered by dhathri123
36
hi friend,

f(x)=√3x²+10x+7√3

=√3x²+7x+3x+7√3

=x(√3x+7)+√3(√3x+7)

=(x+√3)(√3x+7)

so,-√3 and -7/√3 are the zeros of the given polynomial.

I hope this will help u ;)

♥dhathri123♥
Answered by adityavarman
4
Greetings,
The answer to your question is given below ^
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Solved using formula method (b²-4ac)


√3x² + 10x+ 7√3=0

using the formula x= [ -b +/-
√(b²-4ac)]/2a

⇒ x = [-10 +/- √(10² - 4√3 x 7√3) ] / 2√3
⇒ x = [-10 +/- √(100 - 84) ] / 2√3
⇒ x = [-10 +/- √16 ] / 2√3
⇒ x = [-10 +/- 4 ] / 2√3
⇒ x= (-10 + 4) / 2√3 [(α)]  or x= (-10 - 4) / 2√3 [(β)]
⇒ α= -√3                           &  β = (-7√3) /3
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PS: Enjoy ;)
 
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