find the zeros of √3x²+10x+7√3
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Answered by
36
hi friend,
f(x)=√3x²+10x+7√3
=√3x²+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3)(√3x+7)
so,-√3 and -7/√3 are the zeros of the given polynomial.
I hope this will help u ;)
♥dhathri123♥
f(x)=√3x²+10x+7√3
=√3x²+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3)(√3x+7)
so,-√3 and -7/√3 are the zeros of the given polynomial.
I hope this will help u ;)
♥dhathri123♥
Answered by
4
Greetings,
The answer to your question is given below ^
_____________________________________________________________
Solved using formula method (b²-4ac)
√3x² + 10x+ 7√3=0
using the formula x= [ -b +/-√(b²-4ac)]/2a
⇒ x = [-10 +/- √(10² - 4√3 x 7√3) ] / 2√3
⇒ x = [-10 +/- √(100 - 84) ] / 2√3
⇒ x = [-10 +/- √16 ] / 2√3
⇒ x = [-10 +/- 4 ] / 2√3
⇒ x= (-10 + 4) / 2√3 [(α)] or x= (-10 - 4) / 2√3 [(β)]
⇒ α= -√3 & β = (-7√3) /3
_____________________________________________________________
PS: Enjoy ;)
The answer to your question is given below ^
_____________________________________________________________
Solved using formula method (b²-4ac)
√3x² + 10x+ 7√3=0
using the formula x= [ -b +/-√(b²-4ac)]/2a
⇒ x = [-10 +/- √(10² - 4√3 x 7√3) ] / 2√3
⇒ x = [-10 +/- √(100 - 84) ] / 2√3
⇒ x = [-10 +/- √16 ] / 2√3
⇒ x = [-10 +/- 4 ] / 2√3
⇒ x= (-10 + 4) / 2√3 [(α)] or x= (-10 - 4) / 2√3 [(β)]
⇒ α= -√3 & β = (-7√3) /3
_____________________________________________________________
PS: Enjoy ;)
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