Math, asked by shobharajpurohit4293, 10 months ago

find the zeros of √3x2+10x+7√3​

Answers

Answered by Anonymous
5

√3x^2+10x+7√3=0

√3x^2+3x+7x+7√3=0 √3 × 7√3

=21

√3x(x+√3)+7(x+√3)=0

(√3x+7)(x+√3)=0

x= -7/√3 or x= -√3

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