find the zeros of √3x2+10x+7√3
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√3x^2+10x+7√3=0
√3x^2+3x+7x+7√3=0 √3 × 7√3
=21
√3x(x+√3)+7(x+√3)=0
(√3x+7)(x+√3)=0
x= -7/√3 or x= -√3
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