Question

find the zeros of 3x2-9x+20​

Answer 1

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$\large\bold{\mathtt{CORRECT\:QUESTION}}$

➡ Find the zeroes of $\sf 3{x}^{2} - 9x + 20$

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$\large\bold{\mathtt{SOLUTION}}$

☯ Equate the given expression to zero .

→ Sridharacharya formula for Solving Quadratic Equation ax² +bx + c = 0 says that,

→ x = [ -b±√(b²-4ac) / 2a ]

→ x = [ - b± √D /2a ]

✨where, D(Discriminant)= b²-4ac

Putting values now , we get

→ [9 ± √(9²-4*3*(-20)/2*3]

FINAL ANSWER→ [9±√321]/6

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