Question

find the zeros of 4 x square 7 and verify the relationship between the zeros and xcoeffecient

Answer 1

Using identity,
a² + b²=( a+b) (a-b)
We get,
(2x + √7) ( 2x + √7)=0
2x + √7=0
2x = -√7
x = -√7/2
And
2x -√7=0
2x = √7
x = √7/2
Now the relationship,
In the equation,
a= 4 ,b = 0 , c= 7
sum ,
√7/2 - √7/2 = 0/2
= 0/4
= -b/a
And
product,
√7/2 x - √7/2 = 7/4
= c/a
Hence verified.