Question

find the zeros of 4u²+8u and verify the relation between zeros and its coefficients

Answer 1

.......hope it helps.......

Answer 2

Hey friend !

p(x) = 4u²+8u

4u ( u + 2 ) = 0

[4u + 0 ] [ u + 2 ] ------> factorized form

hence ,
u = 0
u = -2


Here ,
a = 4
b = 8
c = 0

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2
= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0
= c/a = 0/4 = 0