find the zeros of 4x^2-3x-7
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Given to find the zeros of Quadratic polynomial :-
4x² - 3x -7
SOLUTION:-
Here the product of two numbers should be -28 And sum of two numbers should be -3
-7 × 4 = -28
-7 + 4 = -3
So, split the middle term as -7x + 4x
4x² - 3x -7
4x² -7x + 4x - 7
4x² + 4x -7x -7
4x( x +1 ) -7 (x + 1)
(x + 1 )(4x -7)
Finding zeros of Quadratic polynomial:-
x + 1 = 0
x = -1
4x - 7 = 0
4x = 7
x = 7/4
So, the value of x are -1 , 7/4
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KNOW MORE :-
- A quadratic polynomial has two zeros
- We can find the two zeros by various methods like factorization method , quadratic formula , complete squaring
- We can find the nature of roots that means roots are real/complex/distinct /equal we can find by discriminant of quadratic polynomial
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