Question

find the zeros of 4x2-7 and verify the relationship between the zeros and its coefficients

Answer 1

Hi ,

1 ) Let p( x ) = 4x² - 7

To find the zeroes of p( x ) ,we have

to take p ( x ) = 0

4x² - 7 = 0

( 2x )² - ( √7 )² = 0

( 2x + √7 ) ( 2x - √7 ) = 0

Therefore ,

2x + √7 = 0 or 2x - √7 = 0

2x = - √7 or 2x = √7

x = - √7/2 or x = √7/2

Required two zeroes of p( x ) are

m = -√7/2 , n = √7/2

2 ) Compare p( x ) = 4x² - 7 with

ax² + bx + c ,

a = 4 , b = 0 , c = -7

i ) Sum of the zeroes = -b/a

m + n = -√7/2 + √7/2 = 0 = - 0/4

ii ) product of the zeroes = c/a

mn = ( -√7/2 ) ( √7/2 ) = 7/4 = c/a

I hope this helps you.

: )

Answer 2

Answer:

Step-by-step explanation: