Question

find the zeros of 64x square+16 x+1​

Answer 1

Answer:

The zeroes of this polynomial are -1/8 and -1/8.

Step-by-step explanation:

64x^2 + 16x + 1

= 64x^2 + 8x +8x + 1

{writing 16x as 8x +8x}.

= 8x(8x+1) + 1(8x +1)

{taking (8x +1) common}.

= (8x+1) (8x+1).

To find the zeroes, we need to equate these with zero...

So,

• 8x+1 = 0
• x = -1/8.

Again,

• 8x+1 = 0
• x= -1/8.