Question

find the zeros of 6x^2-3​

Answer 1

Thus so

THUS THE QUADRATIC EQUATION IS

➡ 6X² - 3

. 6X² + 0 X - 3

. 6X² + ROOT 18X - ROOT 18X - 3

. 3ROOT 2 X ( ROOT 2 X + 1 ) - 3 ( ROOT 2 X + 1 )

. X = 1 / ROOT 2

. X = -1 / ROOT 2

THUS AS 1 / ROOT 2 + ( - 1 / ROOT 2 ) = 0

➡ - B / A = 0

AS 1 / ROOT 2 ❌ - 1 / ROOT 2 = -1 / 2

➡ C / A = -3 / 6 = -1 / 2

THUS IT S IT

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Answer 2

Answer:

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