Question

find the zeros of 6x^2-5x-4​

Answer 1

Answer:

the zeros are

$- \frac{1}{2} \: and \: \frac{4}{3}$

Step-by-step explanation:

${6x}^{2} - 5x - 4$

=> 6x^2 - (8x-3x) - 4

=> 6x^2 - 8x + 3x - 4

=> 2x (3x - 4) + 1 (3x-4)

=> (2x+1)(3x-4)

the zeros are

2x+1=0

=> 2x= -1

$x = - \frac {1}{2}$

and

3x-4=0

=> 3x = 4

$x = \frac{4}{3}$

hope this will help