Find the zeros of "6x²-3-7x"and verify the relationship between the zeroes and co efficient
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Answer: x = (3/2) and (-1/3).
I don't know the relationship unless when substituting the x in the equation it should always equal zero. Hope this helped
Step-by-step explanation: First start off with factoring the equation or using the quadratic formula.
6x²-7x-3
1) 6×(-3) = -18
2) Find two numbers that add to -7 and multiple to -18 which would be -9 and 2
3) write it as (6x-9)(6x+2) = 0
4) divide by greatest common factor
5) (2x-3)(3x+1) = 0
6) find the zeros which would be x = (3/2) and (-1/3)
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