find the zeros of 6xsquare -13x+6 and verify the relationship between zeros and it's coefficient
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Answered by
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Zeros are 2/3 & 3/2......... I think
karan9424:
it may be
Answered by
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Heya !!
6X² - 13X + 6
=> 6X² - 9X - 4X + 6
=> 3X ( 2X - 3 ) - 2 ( 2X - 3)
=> ( 2X - 3 ) ( 3X - 2 ) = 0
=> ( 2X - 3 ) = 0 OR ( 3X - 2 ) = 0
=> X = 3/2 OR X = 2/3
Let alpha = 3/2 and Beta = 2/3
Sum of zeroes = Alpha + Beta = 3/2 + 2/3 = 9 + 4 / 6 = 13/6 = Coefficient of X/Coefficient of X²
And,
Product of zeroes = Alpha × Beta = 3/2 × 2/3 = 6/6 = Constant term / Coefficient of X².
6X² - 13X + 6
=> 6X² - 9X - 4X + 6
=> 3X ( 2X - 3 ) - 2 ( 2X - 3)
=> ( 2X - 3 ) ( 3X - 2 ) = 0
=> ( 2X - 3 ) = 0 OR ( 3X - 2 ) = 0
=> X = 3/2 OR X = 2/3
Let alpha = 3/2 and Beta = 2/3
Sum of zeroes = Alpha + Beta = 3/2 + 2/3 = 9 + 4 / 6 = 13/6 = Coefficient of X/Coefficient of X²
And,
Product of zeroes = Alpha × Beta = 3/2 × 2/3 = 6/6 = Constant term / Coefficient of X².
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