Question

find the zeros of a polynomial 4x²-12x and verify its relationship with the coefficient

Answer 1

Answer:

4x^2-9

a=4

b=0

c=9

now, D, discriminant=b^2-4ac

=0-4x4x9

=-144

now, -b+_√D/2a

= -0+√-144/8

= 12/8

= 3/2

so,α=3/2

now, -b-√D/2a

= -0-√144/8

= -12/8

= -3/2

so, β= -3/2

now, showing relationship between the zeros and it's coefficients,.

now, α+β= -b/c

3/2+(-3/2) = -0/9

3/2-3/2 = 0

0 = 0

also, αxβ = c/a

3/2x-3/2 = -9/4

-9/4 = -9/4

Step-by-step explanation:

Answer 2

zeroes are 0,3.....hope yhis would be helpful. ..
thank u