find the zeros of a polynomial fx =x3-12x2+39x-28if it is given that the zeros are in A. P
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first we put X = 1
then we get this type equation x2-11x+28
now we solve quadratic equation then
finally we get
zeroes = 1,7,4
then we get this type equation x2-11x+28
now we solve quadratic equation then
finally we get
zeroes = 1,7,4
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