Question

find the zeros of a polynomial (X2 + 3 x 10) and verify the relationship between the between its zeros and coefficients​

Answer 1

Answer:

X²-3x-10

x² -(5x-2x)-10

x² - 5x+2x-10

x(x-5)+2(x-5)

(x-5)(x+2)

x=5

x=-2

Sum of zeroes = α+β = 5-2 = 3

α+β = -b/a = -(-3)/1 = 3

Product of zeroes = αβ = 5*-2 = -10

αβ = c/a = -10/1 = -10

Proved

Step-by-step explanation:

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