Find the zeros of a quadratic polynomial 5x2 – 4 – 8x and verify the relationship between the
zeros and the coefficients of the polinomial.
Answers
Answered by
366
Hey!
Given polynomial :- 5x² - 4 - 8x
Any Quadratic polynomial should be in the form of ax² + bx + c
So, the polynomial is 5x² - 8x - 4
Let's factorise it by middle term splitting method :)
5x² - 8x - 4
5x² - 10x + 2x - 4
5x ( x - 2 ) + 2 ( x - 2 )
( 5x + 2 ) ( x - 2 )
• ( 5x + 2 ) = 0
x = -2/5
• ( x - 2 ) = 0
x = 2
So, the zeros are -2/5 and 2 !!
° To verify :-
• Sum of Zeros =
Taking LHS
° Sum of Zeros = -2/5 + 2
Now ,taking RHS
Hence , LHS = RHS !!
• Product of Zeros =
Taking LHS
° Product of Zeros = -2/5 × 2 = -4/5
Now, taking RHS
Hence in both the case LHS = RHS
so, it's Verified !!
Given polynomial :- 5x² - 4 - 8x
Any Quadratic polynomial should be in the form of ax² + bx + c
So, the polynomial is 5x² - 8x - 4
Let's factorise it by middle term splitting method :)
5x² - 8x - 4
5x² - 10x + 2x - 4
5x ( x - 2 ) + 2 ( x - 2 )
( 5x + 2 ) ( x - 2 )
• ( 5x + 2 ) = 0
x = -2/5
• ( x - 2 ) = 0
x = 2
So, the zeros are -2/5 and 2 !!
° To verify :-
• Sum of Zeros =
Taking LHS
° Sum of Zeros = -2/5 + 2
Now ,taking RHS
Hence , LHS = RHS !!
• Product of Zeros =
Taking LHS
° Product of Zeros = -2/5 × 2 = -4/5
Now, taking RHS
Hence in both the case LHS = RHS
so, it's Verified !!
Answered by
127
‼
As we know,
the standard form of a quadratic polynomial is
So,
Let @ and ß be the zeroes of the given polynomial.
Now,
OR
@ + ß
OR
OR
@ * ß
OR
As we know,
the standard form of a quadratic polynomial is
So,
Let @ and ß be the zeroes of the given polynomial.
Now,
OR
@ + ß
OR
OR
@ * ß
OR
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