Question

find the zeros of a quadratic polynomial 6x square - 7 x - 3 and verify the relationship between the zeros and the coefficients​

Answer 1

Answer:

Step-by-step explanation:

6x²-7x-3=0

6x²-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

x= -1/3 or 3/2

Sum of zeros = -1/3+3/2= -2/6+9/6=7/6  (-Coefficient of x / Coefficient of x²)

Product of zeros = -1/3*3/2 = -1/2 (Constant term / Coefficient of x²)