Question

find the zeros of a quadratic polynomial 8 x square - 4 and and verify the relationship between the zeros and the coefficient​

Answer 1

Answer:

Let p(x)=x

2

−3

Zero of the polynomial is the value of x where p(x)=0

Put p(x)=0⇒x

2

−3=0

⇒x

2

−(

3

)

2

=0

So,x=

3

,−

3

∴α=

3

and β=−

3

are zeroes of the polynomial.

We can write p(x)=x

2

−3=x

2

+0−3 is of the form ax

2

+bx+c where a=1,b=0,c=−3

L.H.S=Sum of the zeroes=α+β=

3

−

3

=0

and R.H.S=Sum of the zeroes=

a

−b

=

1

−0

=0

L.H.S=Product of the zeroes=αβ=

3

×−

3

=−3

and R.H.S=product of the zeroes=

a

c

=

1

−3

=−3

Since L.H.S=R.H.S