Question

find the zeros of each of the following quadratic polynomial and verify the relationship between the zeros and the coefficients. ​

Answer 1

Step-by-step explanation:

In the given equation,

a = 1, b = 2√2, c = -6

Now,

if we simplify this equation, we get the zeros as

x^2 + 2√2x - 6 = 0

x^2 + 3√2x - √2x - 6 = 0

x(x + 3√2) - √2(x + 3√2) = 0

(x - √2) (x + 3√2) = 0

x = √2, x = -3√2

Now,

let us consider these zeros as x and y

then, x+y = -b/a, xy = c/a

x+y = -3√2 + √2 = -2√2 = -2√2/1 = -2√2

xy = -3√2*√2 = -6 = -6/1 = -6

Hence proved.

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