Question

Find the zeros of each of the
following quadratic polynomial. Also,
verify the relationship between the
and its
coefficient
x²+8x+12
​

Answer 1

Answer:

your answer

Step-by-step explanation:

x²+8x+12

x²+6x+2x+12

x(x+6)+2(x+6)=0

(x+6)(x+2)=0

x=-6 or x=-2

Answer 2

Answer:

Step-by-step explanation:

ax² + bx + c, if zeros of the quadratic polynomial are $x_{1}$ and $x_{2}$ then  

$x_{1}$ + $x_{2}$ = - $\frac{b}{2a}$

$x_{1}$ × $x_{2}$ = $\frac{c}{a}$

~~~~~~~~~~~~~~~~~

x²+ (6 + 2)x + (2×6) =

x(x + 6) + 2(x + 6) = (x + 6)(x + 2)

Zeros of polynomial are (- 6) and (- 2)

(- 6) + (- 2) = - $\frac{8}{1}$ = - 8

(- 6) × (- 2) = $\frac{12}{1}$ = 12