Math, asked by BrainlyHelper, 1 year ago

Find the zeros of each of the following quadratic polynomial and verify the relationship between the zeros and their coefficients:
(i) f(x) = x² − 2x − 8
(ii) g(s) = 4s² − 4s + 1
(iii) h(t) = t² − 15

Answers

Answered by nikitasingh79
7

SOLUTION:

(i)  

Let f(x)=x² - 2x - 8

By splitting the middle term  

= x² - 4x + 2x - 8

= x(x- 4) + 2(x- 4)

= (x+2)(x - 4)

On putting f(x) = 0  

(x+2)(x - 4) = 0

(x+2) = 0  or  (x - 4)= 0

x = -2 or x = 4

Hence, the Zeroes of the polynomials are α = -2 and β = 4.

Verification :  

Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x²

α+ β = −(−2)1

-2 + 4 = −(−2)1

2 = 2

Therefore, Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x².

Product of the zeroes(αβ) = constant term /Coefficient of x²

-2 × 4 = -8/1

-8 = -8

Therefore, Product of the zeroes(αβ) = constant term /Coefficient of x²

Hence, the relationship is verified.

(ii) Let g(s) = 4s² - 4s+1

By splitting the middle term

= 4s²  - 2s -  2s + 1

= 2s(2s - 1)−1 (2s - 1)

= (2s - 1)(2s - 1)

On putting g(s) = 0  

(2s - 1)(2s - 1)= 0

(2s - 1) = 0

2s = 1

s = 1/2

Hence, the Zeroes of the polynomials are α = 1/2 and β = 1/2

Verification :  

Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x²

1/2+1/2= −(−4)/4

2/2 = 4/4

1 = 1

Therefore , Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x²

Product of the zeroes(αβ) = constant term /Coefficient of x²

1/2×1/2 = 1/4

1/4=1/4

Therefore, Product of the zeroes(αβ) = constant term /Coefficient of x²

Hence, the relationship is verified.

(iii)

Let  h(t) = t²– 15

h(t) =t² –15

=( t)²– (√15)²

= (t +√15) (t -√15)

[a² - b² = (a +b) (a-b)]

On putting h(t) = 0  

(t +√15) (t -√15) = 0

(t +√15)  = 0

t = -√15

(t -√15) = 0

t = √15

Hence, the Zeroes of the polynomials are α = -√15 and β =√15.

Verification :  

Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x²

-√15 + √15 = 0/1

0 = 0

Therefore, Sum of the zeroes(α+ β )= −coefficient of x/ coefficient of x².

Product of zeroes (αβ)= constant term /Coefficient of x²  

−√15 × √15 = −15/1

-15 = -15

Therefore, Product of zeroes (αβ)= constant term /Coefficient of x²

Hence, the relationship verified.

HOPE THIS ANSWER WILL HELP YOU….

Answered by sapnachand75
2

(-2)^2-2×(-2)-8=4+4-8


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