find the zeros of f x is equal to x cube minus 2 x square
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f(x) = x^3-2x^2
(Taking x^2 common)
= x^2(x-2).
Now equate f(x) to 0 to get the zeros of your polynomial.
So,
f(x) = 0
x^2(x-2) = 0
Here either x^2 = 0
x=0
or (x-2) = 0
x=2
So the zeroes of this polynomial are 0 and 2.
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