Question

Find the zeros of given p(x) =x2+6x-216 and also verify relation b/w zeros and coefficients of p(x)

Answer 1

Answer:

Zeroes:- x = 12, x = -18

Relation b/w Zeroes and Co-efficient of p(x) is Verified

Step-by-step explanation:

Find Zeroes

$x^2 + 6x - 216\\x^2 + 18x - 12x - 216\\x(x + 18) - 12(x + 18)\\(x - 12)(x + 18)\\x = 12 (or) x = -18$

Relationship between the Zeroes

Now Each Zero should be Taken as $\alpha$ and $\beta$

So,

$\alpha = 12, \beta = -18$

$\alpha + \beta = -b/a$

12 + (-18) = -(6)/1

-6 = -6     Therefore, Verified

$\alpha\beta = c/a$

12 x -18 = -216/1

-216 = -216    Therefore, Verified